(x-3)^2/3=x-7

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Solution for (x-3)^2/3=x-7 equation: 


x in (-oo:+oo)

((x-3)^2)/3 = x-7 // - x-7

((x-3)^2)/3-x+7 = 0

((x-3)^2)/3+(3*(-x))/3+(3*7)/3 = 0

(x-3)^2+3*(-x)+3*7 = 0

x^2-9*x+9+21 = 0

x^2-9*x+30 = 0

x^2-9*x+30 = 0

x^2-9*x+30 = 0

DELTA = (-9)^2-(1*4*30)

DELTA = -39

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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